How to play Craps

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Craps is a game dating right back to Ancient Rome before the days of online pokies! Soldiers used to carve pig bones into dice and gamble with them. Today you can play craps online at choiceonlinecasino.com or in a casino where craps is played around a specialised table with raised sides. Although the game is very simple, it offers a wide range of interesting bets.

Here is an overview of craps bets with medium odds that you can make. Have a 16.7% chance of winning an Any 7 bet, with a payout of 4/1. This gives the house a substantial edge of 16.9%. This is quite high compared to some of the bets we’ve seen above, yet still a solid choice if you’re chasing more slightly more daring bets. In doing so, it creates a wager which has huge real odds. This is the wager which excites players at the table who do not have a stake riding on this bet. The payoff for the All Bet is 174 to 1. For this wager to win, then the shooter must roll all the following numbers before rolling a seven: 2,3,4,5,6,8,9,10,11, and 12. These bets will usually have the biggest payout odds in craps, but the chances of landing them are slim. For instance, landing a 'snake eyes' (two 1's) offers payout odds of 30:1 but the chance of landing it is 1 in 36, with a 13.9% house edge.

Understand and Beat the Odds - How to Play Craps Pt. 5Understanding and Beating the Odds is fundamental if you want to win more at the game of craps.

In a casino, the game is run by two or more operators. The players take it in turns to roll the dice. The player to roll the dice is called the shooter. Usually the shooter is given a choice of five dice, from which two are selected for the game. When the dice are rolled they should hit the far side of the table before landing, to ensure a fair play.

The Basic Game and the Pass Line Bet pays 1/1 The operator indicates the start of a round by placing a plastic disc on the table showing the word OFF. The shooter (and any other players who want to bet on him) places a bet on the Pass Line.

The first roll of the dice is called the Come-Out Roll. The two dice are rolled and the total on the dice is counted. Here are the possible outcomes:

• 7 or 11 This is called a natural. All bets on the Pass Line WIN. This pays 1/1 so if you bet $5, you receive $5 plus your $5 stake back. The round is finished.
• 2,3 or 12 This is called craps and all bets on the Pass Line LOSE. The round is finished.
• 4,5,6,8,9 or 10 Whatever number rolled is called the Point and the round continues...

If a point is thrown, the operator flips the plastic disc over to show the word ON and places it on the table to indicate which point is active. The shooter keeps rolling again until: Point If the shooter rolls his call-out score again, all bets on the Pass Line WIN which pays 1/1. 7 This is called a seven-out and all bets on the Pass Line LOSE. After rolling a seven-out, the shooter passes the dice to the next player.

What are your chances of winning on the Pass Line?

Before we look at any other bets, let's see how likely we are to win the simplest Pass Line bet.

Two normal dice can land in 6 x 6 = 36 different ways.

To win on the Come-Out roll, we need to throw 7 or 11. There are 6+2 = 8 ways of doing this so the chance is 8/36 = 22.22%

To lose on the Come-Out roll, we need to throw 2,3 or 12. There are 1+2+1 = 4 ways of doing this, so the chance is 4/36 = 11.11%

The chances of getting a point and needing to roll again are 24/36 = 66.67%.

To work out our chances of winning on a point, we look at the individual point score chances.

pass line win probability = 244/495
(244/495)^3 = 0.119771609 exactly 3
you want 3 or more
formula for the sum of a geometric series is a/1-r
where a is the first term
r = the ratio
a = (244/495)^3
r = 244/495
so (244/495)^3 / (1-(244/495) = 0.236202973
But now you want this to end. Multiply the above result by 1-(244/495)
0.119771609
((244/495)^3 / (1-(244/495)) * (1-(244/495))
added my table

at least in a row then lose	Prob	1 in
2	0.242979288	4.1
3	0.119771609	8.3
4	0.059038934	16.9
5	0.02910202	34.4
6	0.014345238	69.7
7	0.007071188	141.4
8	0.003485596	286.9
9	0.001718152	582.0
10	0.000846928	1,180.7
11	0.000417475	2,395.4
12	0.000205786	4,859.4
13	0.000101438	9,858.3
14	5.00017E-05	19,999.3
15	2.46473E-05	40,572.4
16	1.21494E-05	82,308.7
17	5.98878E-06	166,978.8
18	2.95205E-06	338,748.0
19	1.45515E-06	687,214.1
20	7.17286E-07	1,394,143.4

Blackjack Chance Of Winning Calculator

pass line win probability = 244/495
(244/495)^3 = 0.119771609 exactly 3

Mustangsally: Maybe I'm missing something, but I get different results from what you show. Suppose (for simplicity) that it was a coin flip with p=0.5 instead of 244/495. To get at least one win in a row would be P=0.5. To get at least two in a row is P=0.5^2, etc. To get the answer for exactly n in a row, you need to multiply the 'at least' by the probability of losing on the n+1 try.
For the pass line problem, I think the 0.119771609 figure is for 3 or more, not for exactly 3.
Isn't that correct, or what did I miss?

For the pass line problem, I think the 0.119771609 figure is for 3 or more, not for exactly 3.
Isn't that correct, or what did I miss?

rudeboyoi and Sally both arrived at the same value.
Sally did it differently by starting with 3 pass line wins in a row in 3 trials.
The OP asked a unique question.
Most ask the probability of winning 3 pass line bets in a row. And for 3 trials it is simply p^3
OP wanted to add the probability of 3 *or more* and *followed by a loss*.
Sally's math shows 3 in a row in 3 trials and the OPs Q arrives at the same value. It should.
IF the OP had asked what is the probability of winning 3 pass line bets in a row then losing, we would have p^3 * q or 0.06073
Let us see if OP is happy and replies.
added
average number of trials to see a run of 3 or more pass line wins: 16.466
4 or more: 33.404
5 or more: 67.765
6 or more: 137.475
Multiple streaks of pass line winners.
15 trials about 30 minutes of play at 100 rolls per hour
30 trials about 1 hour of play
Example: 30 pass line trials
about a 90% chance of at least 3 pass line wins in a row at least one time
about a 58% chance of at least 3 pass line wins in a row at least two times

Blackjack Chance Of Winning

about a 23% chance of at least 3 pass line wins in a row at least three times
here is the losing streaks (miss) for the pass line per N trials

added
average number of trials to see a run of 3 or more pass line wins: 16.466
4 or more: 33.404
5 or more: 67.765
6 or more: 137.475

You guys are great. Thanks for the detailed responses.
How did you calculate the average number of trials to see a run of 3, 4, 5, 6 or more pass line wins?
How do you define a trial? Would each shooter be a new trial? Or does a new trial begin after any losing pass line bet, in which case a single shooter could have multiple trials that end and start over with a losing pass line bet from throwing 2, 3, or 12 on a come out roll?
If a bettor were to power press the pass line bet with a $100 wager:

at least in a row then lose	Prob	1 in	Bet	Win	Lose
1	0.492929293	2.0	$100.00	$100.00	$100.00
2	0.242979288	4.1	$200.00	$300.00	$100.00
3	0.119771609	8.3	$400.00	$700.00	$100.00
4	0.059038934	16.9	$800.00	$1,500.00	$100.00
5	0.02910202	34.4	$1,600.00	$3,100.00	$100.00
6	0.014345238	69.7	$3,200.00	$6,300.00	$100.00

Does this mean that on average you would be betting about $1600 to win $700 on a press of 3 pass line wins for a net loss of $900?
$3,300 to win $1,500 on 4 pass line wins losing $1,800?
$6,700 to win $3,100 on 5 pass line wins losing $3,600?
$13,700 to win $6,300 on 6 pass line wins losing $7,400?

Best Chance Of Winning Craps

What's the best way to interpret this expected value for power pressing a pass line bet?